{"id":4167,"date":"2018-11-30T15:00:25","date_gmt":"2018-11-30T20:00:25","guid":{"rendered":"http:\/\/iblog.dearbornschools.org\/salehm\/?p=4167"},"modified":"2018-11-30T11:07:43","modified_gmt":"2018-11-30T16:07:43","slug":"todays-reinforcement-of-your-last-c-e-r-review-for-test","status":"publish","type":"post","link":"https:\/\/iblog.dearbornschools.org\/salehm\/2018\/11\/30\/todays-reinforcement-of-your-last-c-e-r-review-for-test\/","title":{"rendered":"Today&#8217;s Reinforcement of Your Last C.E.R.: Review for Test"},"content":{"rendered":"<p><b>Question 1:<\/b><span style=\"font-weight: 400;\"> How can a small object (<\/span><span style=\"font-weight: 400;\">small mass<\/span><span style=\"font-weight: 400;\">) have the same kinetic energy as a large object (<\/span><span style=\"font-weight: 400;\">large mass<\/span><span style=\"font-weight: 400;\">)?<\/span><\/p>\n<p><span style=\"font-weight: 400;\">If two objects have a KE of 50 J, and one object has mass of 1 kg moving at 10 m\/s while the other has mass of 100 kg moving at 1 m\/s, then they both have the same K.E.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE= \u00bd m v\u00b2 \u00a0<\/span> <span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 KE= \u00bd m v\u00b2 <\/span><\/p>\n<p><span style=\"font-weight: 400;\">50 J = \u00bd (<\/span><b>1 kg<\/b><span style=\"font-weight: 400;\">) (10 m\/s)\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a050 J = \u00bd (<\/span><b>100 kg<\/b><span style=\"font-weight: 400;\">) (1 m\/s)\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">50 J = \u00bd (1 kg) 100 m\u00b2\/s\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a050 J = \u00bd (100 kg) 1 m\u00b2\/s\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">50 J = 50 J\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a050 J = 50 J<\/span><\/p>\n<p><span style=\"font-weight: 400;\">***Note that the smaller object tends to have a higher velocity.***<\/span><\/p>\n<p><span style=\"font-weight: 400;\">***Note that the larger object tends to have a lower velocity.***<\/span><\/p>\n<p>&nbsp;<\/p>\n<p><b>Question 2:<\/b><span style=\"font-weight: 400;\"> How can an object with a <\/span><span style=\"font-weight: 400;\">small velocity <\/span><span style=\"font-weight: 400;\">have the same kinetic energy as an object with a <\/span><span style=\"font-weight: 400;\">large velocity<\/span><span style=\"font-weight: 400;\">?<\/span><\/p>\n<p><span style=\"font-weight: 400;\">If two objects have a KE of 50 J, and one object has mass of 1 kg moving at 10 m\/s while the other has mass of 100 kg moving at 1 m\/s, then they both have the same K.E.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE= \u00bd m v\u00b2 \u00a0<\/span> <span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 KE= \u00bd m v\u00b2 <\/span><\/p>\n<p><span style=\"font-weight: 400;\">50 J = \u00bd (<\/span><span style=\"font-weight: 400;\">100 kg<\/span><span style=\"font-weight: 400;\">) (<\/span><b>1 m\/s<\/b><span style=\"font-weight: 400;\">)\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a050 J = \u00bd (<\/span><span style=\"font-weight: 400;\">1 kg<\/span><span style=\"font-weight: 400;\">) (<\/span><b>10 m\/s<\/b><span style=\"font-weight: 400;\">)\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">50 J = \u00bd (100 kg) 1 m\u00b2\/s\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a050 J = \u00bd (1 kg) 100 m\u00b2\/s\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">50 J = 50 J\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a050 J = 50 J<\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight: 400;\">***Note that the larger object tends to have a lower velocity.***<\/span><\/p>\n<p><span style=\"font-weight: 400;\">***Note that the smaller object tends to have a higher velocity.***<\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight: 400;\">\f<\/span><\/p>\n<p><b>Question 3:<\/b><span style=\"font-weight: 400;\"> What happens to the kinetic energy if you double the mass?<\/span><\/p>\n<p><span style=\"font-weight: 400;\">One ball has a mass of 5 kg and the other has as mass of 10 kg. They are both thrown at a speed of 20 m\/s. What is the difference in their KE?<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE= \u00bd m v\u00b2 \u00a0<\/span> <span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0KE= \u00bd m v\u00b2 <\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE = \u00bd (<\/span><span style=\"font-weight: 400;\">5 kg<\/span><span style=\"font-weight: 400;\">) (<\/span><b>20 m\/s<\/b><span style=\"font-weight: 400;\">)\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 KE = \u00bd<\/span><span style=\"font-weight: 400;\"> (10 kg)<\/span><span style=\"font-weight: 400;\"> (<\/span><b>20 m\/s<\/b><span style=\"font-weight: 400;\">)\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE = \u00bd (5 kg) 400 m\u00b2\/s\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 KE = \u00bd (10 kg) 400 m\u00b2\/s\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE = 1,000 J\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0KE = 2,000 J<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The KE of the more massive ball is <\/span><span style=\"font-weight: 400;\">double<\/span><span style=\"font-weight: 400;\"> the the KE of the less massive ball.<\/span><\/p>\n<p>&nbsp;<\/p>\n<p><b>Question 4:<\/b><span style=\"font-weight: 400;\"> What happens to the kinetic energy if you double the velocity?<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Two balls have a mass of 5 kg. One is thrown at 10 m\/s and the other is thrown at a speed of 20 m\/s. What is the difference in their KE?<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE= \u00bd m v\u00b2 \u00a0<\/span> <span style=\"font-weight: 400;\">\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0KE= \u00bd m v\u00b2 <\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE = \u00bd (<\/span><b>5 kg<\/b><b>)<\/b><span style=\"font-weight: 400;\"> (10 m\/s)\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0KE = \u00bd<\/span><span style=\"font-weight: 400;\"> (<\/span><b>5 kg<\/b><span style=\"font-weight: 400;\">)<\/span><span style=\"font-weight: 400;\"> (20 m\/s)\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE = \u00bd (5 kg) 100 m\u00b2\/s\u00b2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0KE = \u00bd (5 kg) 400 m\u00b2\/s\u00b2<\/span><\/p>\n<p><span style=\"font-weight: 400;\">KE = 250 J\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0KE = 1,000 J<\/span><\/p>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight: 400;\">The KE of the faster moving ball is <\/span><span style=\"font-weight: 400;\">4 times<\/span><span style=\"font-weight: 400;\"> the KE of the slower moving ball.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Question 1: How can a small object (small mass) have the same kinetic energy as a large object (large mass)? If two objects have a KE of 50 J, and one object has mass of 1 kg moving at 10 &hellip; <a href=\"https:\/\/iblog.dearbornschools.org\/salehm\/2018\/11\/30\/todays-reinforcement-of-your-last-c-e-r-review-for-test\/\">Continue reading <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":74,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-4167","post","type-post","status-publish","format-standard","hentry","category-class-news"],"_links":{"self":[{"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/posts\/4167","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/users\/74"}],"replies":[{"embeddable":true,"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/comments?post=4167"}],"version-history":[{"count":0,"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/posts\/4167\/revisions"}],"wp:attachment":[{"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/media?parent=4167"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/categories?post=4167"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/iblog.dearbornschools.org\/salehm\/wp-json\/wp\/v2\/tags?post=4167"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}